Write a balanced equation for the combustion of liquid methanol.

Question: Write a balanced equation for the combustion of liquid methanol.

The balanced equation for the combustion of liquid methanol (CH3OH) in the presence of oxygen (O2) is:

2 CH3OH + 3 O2 → 2 CO2 + 4 H2O

In this equation, two molecules of methanol (CH3OH) react with three molecules of oxygen (O2) to form two molecules of carbon dioxide (CO2) and four molecules of water (H2O). The equation is balanced because the number of atoms of each element is equal on both the reactant and product sides of the equation.

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