Pranav invested 30% more than mohan. mohan invested 20% less than raghu. if the total sum of their investment is rs. 10224, how much amount did raghu invested?
Question: Pranav invested 30% more than mohan. mohan invested 20% less than raghu. if the total sum of their investment is rs. 10224, how much amount did raghu invested?
Let's represent the amount invested by Mohan as "x".
Then, according to the problem, Pranav invested 30% more than Mohan, so the amount invested by Pranav can be expressed as 1.3x (130% of x).
Also, Mohan invested 20% less than Raghu, so the amount invested by Raghu can be expressed as 1.25x (125% of x).
Now, we know that the total sum of their investments is Rs. 10,224. So, we can write an equation based on this information:
x + 1.3x + 1.25x = 10224
Simplifying this equation, we get:
3.55x = 10224
Dividing both sides by 3.55, we get:
x = 2880
So, Mohan invested Rs. 2880, Pranav invested 30% more than Mohan i.e., 1.3 * 2880 = Rs. 3744 and Raghu invested 20% more than Mohan i.e., 1.25 * 2880 = Rs. 3600.
Therefore, Raghu invested Rs. 3600.
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