Which statements correctly describe the amounts of the different ions present in 1.52 l of a 0.350 m solution of cacl2? select all that apply.
Question: Which statements correctly describe the amounts of the different ions present in 1.52 l of a 0.350 m solution of cacl2? select all that apply.
If you are studying chemistry, you may encounter questions like this one: which statements correctly describe the amounts of the different ions present in 1.52 L of a 0.350 M solution of CaCl2? Select all that apply.
This question is asking you to apply the concept of molarity, which is the number of moles of solute per liter of solution. A mole is a unit that measures the amount of a substance in terms of its atoms or molecules. One mole of any substance contains 6.02 x 10^23 particles, which is called Avogadro's number.
To answer this question, you need to know how many moles of CaCl2 are in the solution, and how many ions are produced when CaCl2 dissolves in water. You can use the formula:
Molarity = moles of solute / liters of solution
To find the moles of CaCl2, you multiply the molarity by the liters of solution:
moles of CaCl2 = 0.350 M x 1.52 L = 0.532 moles
When CaCl2 dissolves in water, it splits into one calcium ion (Ca2+) and two chloride ions (Cl-). This means that for every mole of CaCl2, there are two moles of Cl- and one mole of Ca2+. You can use this ratio to find the moles of each ion:
moles of Cl- = 2 x moles of CaCl2 = 2 x 0.532 moles = 1.064 moles
moles of Ca2+ = 1 x moles of CaCl2 = 1 x 0.532 moles = 0.532 moles
To find the amount of each ion in grams, you need to multiply the moles by the molar mass, which is the mass of one mole of a substance. You can find the molar mass by adding up the atomic masses of the elements in the compound. The atomic masses are given in the periodic table.
molar mass of Cl- = 35.45 g/mol
molar mass of Ca2+ = 40.08 g/mol
amount of Cl- in grams = moles of Cl- x molar mass of Cl- = 1.064 moles x 35.45 g/mol = 37.7 g
amount of Ca2+ in grams = moles of Ca2+ x molar mass of Ca2+ = 0.532 moles x 40.08 g/mol = 21.3 g
Now that you have the amounts of each ion in grams, you can compare them to the statements given in the question and select the ones that are correct.
The statements that correctly describe the amounts of the different ions present in 1.52 L of a 0.350 M solution of CaCl2 are:
- There are more chloride ions than calcium ions in the solution.
- The total mass of chloride ions in the solution is greater than the total mass of calcium ions in the solution.
- The number of chloride ions in the solution is twice the number of calcium ions in the solution.
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